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  1. #18
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    Quote Originally Posted by betazone View Post
    I am supporting the theory of higher tension -> harder smash. No point arguing you just go string a 22lb vs 26 lb and try it out yourself. I hv done it and case closed for this discussion seriously.
    Ah... but what about if you tried 26 lb vs 30 lb?

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    same old arguements again. I thought we have became civilized and decided everyone is different.

    ie everyones power/smash bell curve is different. some people require more tension to make a harder smash, some need less tension to create a harder smash.

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    btw more powerful sound does not necessary equal more power. the other day I was playing with someone who makes really loud sound on his clears, but the shots were only reaching about mid court. He was then blaming the shuttles were slow. And there was me comfortably making clears to near the backline with less effort and far less sound.


    as for smashes, you really have to have your smashes measured to be certain. This is because we often preceived a louder sound must mean a faster smash. But in reality it might not be the case.

  4. #21
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    I kinda agree w/ louder sound is not always = higher power on the stroke. Too loud of a sound is kinda waste of energy, I would rather have that energy get transferred to the shuttlecock than making loud sounds to be impressive. Just my 2cents.

  5. #22
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    Quote Originally Posted by riffsuad View Post
    one question, can 2 shuttles travel with same speed but different force or power?
    Power = Force x Speed

    So if both shuttles weight the same, then I guess the answer is "no"?

  6. #23
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    Quote Originally Posted by wlachan View Post
    Power = Force x SpeedSo if both shuttles weight the same, then I guess the answer is "no"?
    then what yonex try to tell us about 19kg.f produce by new vt zf? there is no different with other racket if we can produce the same speed.
    Last edited by riffsuad; 02-25-2012 at 04:57 AM.

  7. #24
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    String tension is an interesting topic. I am thinking, if higher tension means more powerful smash, how come the retired badminton player Xiao Jie strung her rackets at 22lbs (according to her training video)? But then all the male professional players string their rackets at much higher tension? Perhaps the actual power has to do with how fast and forceful one can swing the racket as well. It is the sum of all that counts. The tension alone is meaningless regarding smashing power. And each player is different. Lower tension doesn't make one inferior because badminton is not a game of power.

  8. #25
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    Quote Originally Posted by riffsuad View Post
    then what yonex try to tell us about 19kg.f produce by new vt zf? there is no different with other racket if we can produce the same speed.
    Marketing? Who is able or going to verify anyway?

  9. #26
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    Quote Originally Posted by wlachan View Post
    Marketing? Who is able or going to verify anyway?
    whoever intelligent like u...

  10. #27
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    Quote Originally Posted by wlachan View Post
    String tension is an interesting topic. I am thinking, if higher tension means more powerful smash, how come the retired badminton player Xiao Jie strung her rackets at 22lbs (according to her training video)? But then all the male professional players string their rackets at much higher tension? Perhaps the actual power has to do with how fast and forceful one can swing the racket as well. It is the sum of all that counts. The tension alone is meaningless regarding smashing power. And each player is different. Lower tension doesn't make one inferior because badminton is not a game of power.
    so this just my 2cents. there are 2 ways to produce high speed of shuttle during smash..
    1) for lower tension - use this theory f=ma - player to use own power the transfer the energy to the shuttle.
    2) for high tension - use momentum equation, M1V1=M2V2 - player to have greater swing speed.

  11. #28
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    ^^ f=ma is neither an energy nor power equation And why can't you use one equation for both conditions?

  12. #29
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    Quote Originally Posted by visor View Post
    ^^ f=ma is neither an energy nor power equation And why can't you use one equation for both conditions?
    yes can, for those who have own huge power and fast swing speed(good technique) then go for high string tension.

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    I always thought the concept was simple
    each tension has some swing speed interval and if youre not in it, you wont get much out of it

  14. #31
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    Quote Originally Posted by blableblibloblu View Post
    I always thought the concept was simpleeach tension has some swing speed interval and if youre not in it, you wont get much out of it
    Yes, you have to match swing speed with stringbed rebound time, which is directly controlled by string tension.

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    Quote Originally Posted by visor View Post
    Yes, you have to match swing speed with stringbed rebound time, which is directly controlled by string tension.
    yup, i really dont see why people argue on which is more powerful... tighter offers more potential power but its harder to get something out of it. really depends on the person

  16. #33
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    ½ mv² is the equation yonex uses.

    professionals probably have such a fast/hard swing, they need a stiff racket and high tension to maximise the transfer of energy.

    while us more normal people would not benefit from it.

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