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  1. #35
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    Quote Originally Posted by ants
    It all actually depends.. guess what.. 2 days ago i tried tensioning the other way round Main 28 Cross 26lbs.
    And what did you find?
    Did it play differently?

  2. #36
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    Default a question i've thought of

    If stringing at 2 lbs difference , won't the course of the shuttle differ when the shuttle hit the area where there's crosses and mains due to the fact that the amount that the string would be able to stretch differs from the different tension ?

  3. #37
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    Quote Originally Posted by tangle
    If stringing at 2 lbs difference , won't the course of the shuttle differ when the shuttle hit the area where there's crosses and mains due to the fact that the amount that the string would be able to stretch differs from the different tension ?
    what we're trying to say is that the 2 extra pounds are mostly made up when u string the crosses on. you would normally avoid hitting the shuttle near the edge (where there is only 1 type of string) because it isn't going to give you power (too far from sweetspot), so that should normally not be too big of a worry.
    hope this helps

  4. #38
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    Default 27 lbs X 27 lbs on a MP-100

    Last night I bumped into an unregistered BF lurker at VRC. He showed me his MP-100 that was outwardly round cross wise. It was initially strung at 27 lbs X 27 lbs and its shape was all right. I guess after a couple of hard sessions the cross strings relaxed more than the main strings. So, a safe bet is still to add 2 extra pounds on the cross to keep shape of the racquet. Just my two cents.

  5. #39
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    Quote Originally Posted by Pete LSD
    So, a safe bet is still to add 2 extra pounds on the cross to keep shape of the racquet. Just my two cents.
    It may depend on how it was strung.
    Maybe it was done on a 2 point machine.
    My machine has side supports.

    I have been stringing my own racquets with the cross at lower tension than the mains since Jan 2005 and have had no problems.
    Mostly at 22x20, but i have had my Ti-10 and MP100 at 26x24 and 26x25 and not seen any problems with the head shape.

  6. #40
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    This dude's stringer uses a crank machine. Not sure if it has side supports.

    Quote Originally Posted by Neil Nicholls
    It may depend on how it was strung.
    Maybe it was done on a 2 point machine.
    My machine has side supports.

    I have been stringing my own racquets with the cross at lower tension than the mains since Jan 2005 and have had no problems.
    Mostly at 22x20, but i have had my Ti-10 and MP100 at 26x24 and 26x25 and not seen any problems with the head shape.

  7. #41
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    Quote Originally Posted by ants
    It all actually depends.. guess what.. 2 days ago i tried tensioning the other way round Main 28 Cross 26lbs.
    Come on Ants, tell us.
    What did you find?
    Did it play differently?

  8. #42
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    Default reduce the main string 2 lbs

    when a customer wants re-string 23lbs, it's mean main 21lbs and cross 23lbs, but not all cross string is 23lbs, it's from head's 6th staring string, it's mean from the sweatspot to bottom.

  9. #43
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    Default String tension

    Hello everybody,

    I'm stringing my racket also with 5-10% less tension on the crosses.
    Somewhere I was reading an Article in the net that the recommendation ( stringing the crosses 2 lbs higher) is only because the deformation of the headshape.
    The main aim should be gaining an equal stringbed tension. Therefore because the crosses are shorter than the mains they have to be strung with a lower tension.

    I tried to proof this with some physics. Here are my calculations

    Because the string lenghten itself while under tension the diameter => the cross sectional area of the string is getting smaller.

    A = V /(L1 * k * F1) ; A = Cross sectional Area, V = Volume of the unstretched String,
    k = lenghtening of the string (%), F1 Force (N) which pulls on the string

    the tension of the string is coupled with it's lenght through:

    2 * L1 * f = sqrt(F1/ A * ro) ; f = Frequency, ro = density (constant)

    (c = sqrt(F1/ A * ro) ; , c = propagationspeed of the wave
    with c= lambda f; lambda = wave length = 2 *L1)

    The frequency ( Sound) of the long (main L2) and the cross (L1) string should be the same, therefore we can insert the two equations into each other and get :


    L1/L2 = sqrt[(F1* F1 * L1 * k * v2 * ro)/ (F2 * F2 * L2 * k * v1 * ro)]= sqrt([v2 * L1]/v1 * L2]) * F1/F2

    we can cancel some terms and get:

    => F1 = F2 * (sqrt(v2 * L2/ v1* L1))^-1 ; with v1 = (d/2)^2 * pi * L1 , d diameter of
    the string

    the equation simplifies to:

    F1 = F2 * ( L1/ L2)

    If we take L1 = 18,8 cm for the cross string and L2 = 23,5 cm for the main strings
    we get a tension ratio of:

    F1/F2 = L1/L2 = 0.8

    If the mains are strung with 22lbs (10kg) the crosses have to be strung with 17.6 lbs (8kg) to get the same overall stringbedtension.

    Of course this is just for the longest strings, but I think it should be clear now that the crosses should have a lower tension.

    Hopefully there are no mistakes in my equations but the result is just to nice to be wrong.
    Lets hear what you think about it.

    Regards mark

  10. #44
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    Exclamation Why 2 more lbs on the crosses

    Hello,

    it seems as nobody is reeding my post. So I had to find an error myself. The results were just to nice

    I think I have an error in the equation to calcualte the cross sectional area A in dependence of the Force, because if you apply zero force the length of the string would be zero!

    A = V /(L1 * k * F1) ; A = Cross sectional Area, V = Volume of the unstretched String,

    has to be corrected to:

    A = V /(L1 * (1+ k * F1))

    the rest follows analogue to my previous post. But the result is not as nice as before. The equation for the wanted string tension (Force) is:

    F2 = 1/2K2 * [sqrt(1+4k2(L2R2/L1R1)^2*F1*(1+kF1))-1)

    Hopefully the equation is now correct
    If we are using the relative lenghtening from Neils post for BG 65 (0,70cm) 17% and 23.5cm for the mains, 18.5cm for the crosses and the applied force is 100 N ( roughly 10kg = 22lb), the the tension for the crosses should be 78,1N or 7,8kg which is nearly the same ratio as before (0,8)

    With the computed equation it's also possible to calculate the necesseary tension for the proportinal stringing method or the resulting tension if you are using an other string.
    For example if you are using normally the BG65 and string this one with 22lb and use this tension for BG68TI the equivalent tension with BG65 would be 31 lb!! Due to the extreme lenghtening of the string 33 %.

    If there are still some errors I would be glad to get some corrections.

    Regards mark

  11. #45
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    Quote Originally Posted by baumbaer
    If we are using the relative lenghtening from Neils post for BG 65 (0,70cm) 17% and 23.5cm for the mains, 18.5cm for the crosses and the applied force is 100 N ( roughly 10kg = 22lb), the the tension for the crosses should be 78,1N or 7,8kg which is nearly the same ratio as before (0,8)
    the figures I got for lengthening were 1.17% per kg, not 17%
    so for 10kg tension, the string would stretch 11.7%

  12. #46
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    Default why 2 lbs more on the cross

    Quote Originally Posted by Neil Nicholls
    the figures I got for lengthening were 1.17% per kg, not 17%
    so for 10kg tension, the string would stretch 11.7%
    Uups, you are right. Ok with the new value I get 7.3 kg on the cross.
    Perhaps someone is able to verify the results.

    Regards mark

  13. #47
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    hi mark

    all u have done was deriving the basic ratio quotient the long way
    x1/x2=y1/y2

    actually, equal main and cross tension is just one of many objective desired by the stringer/user
    Last edited by cooler; 06-15-2005 at 03:03 AM.

  14. #48
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    Quote Originally Posted by Neil Nicholls
    BG66 0.81%/kg
    BG70Pro 0.92%/kg
    BG65 1.17%/kg
    BG80 1.23%/kg
    BG68Ti 1.33%/kg

    the values are (change in length) / (original length) per Kilogram tension

    the 66 and 70pro where done quite a while ago, and I don't have any more lying around.
    The 65, 80 and 68Ti were done today

    It would be nice if someone else would have a go and see if they get anything similar.
    one question, i thot bg66 would stretch the most u should retest bg66. The rest are within range

  15. #49
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    i just popped into this forum section after reading the equipment section...

    and i noticed this thread... adding 2 pounds to the crosses to maintain the stringbed's normal shape so it isnt deformed. therefore, i'm going to string my new mp99 with bg66@main 22lbs and cross 24lbs? but what will the tension be? both equal since the mains are longer? therefore both will be at 22pounds, or what?

    and also the mathmatical equation by baumbaer and neil.

    to put it in short,the conclusion you have reached is that if one kind of string is done at a certain tension, another string will have to be at a different tension to be exactly the same tension after stretching? correct?

    very complicated indeed...and im making no sense of that mathmatical equation...

  16. #50
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    Quote Originally Posted by cooler
    one question, i thot bg66 would stretch the most u should retest bg66. The rest are within range
    My experience of playing with and stringing BG66 make me expect it to stretch the least. But I'll try to remember to test some next time I open a packet. (I think i've got some now)

  17. #51
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    i want my racquet to be strung at 24 lbs even

    therefore, with this pattern, i would string it at

    24@ mains

    26@ crosses

    after a couple ours of rest, then it would relax to 24 together?

    btw, is the mp99 string pattern 22 mains 22 crosses?

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